$user_lv = $_COOKIE[ (!is_numeric($user_lv)) $user_lv = ($user_lv >= ) $user_lv = ($user_lv > Use code with caution. Copied to clipboard The server checks for a cookie named . If it doesn't exist, it sets it to is_numeric($user_lv) : The value must be a number. $user_lv >= 4 : If the value is 4 or higher, it resets to 1 (Failure). $user_lv > 3 : If the value is strictly greater than 3, you trigger (Success). 3. The Solution To succeed, your greater than 3 but less than 4 (or any decimal between 3 and 4 like 4. Execution Steps Open Developer Tools: in your browser (Chrome/Edge/Firefox). Go to Console: document.cookie="user_lv=3.5"; and press Enter. Alternative (Application Tab): Application , and manually change the value from

If you find a parameter that behaves differently with ' and '' :

the filter check, you can bypass it using double URL encoding. Single Encode right arrow %61%64%6d%69%6e (often still caught by the filter). Double Encode . The string %2561%2564%256d%2569%256e

Known for needing precise, logical exploitation. Common Methodologies for Solving

If the source code looks like charCode + 1 or charCode + 2 :