Msor To Sor [better]: Convert

So, why would one want to convert an MSOR matrix to an SOR matrix? There are several reasons:

For a 2-group MSOR (red-black), the iteration matrix is ( \mathcalL MSOR ). To convert, we seek a scalar ( \omega ) such that the spectral radius ( \rho(\mathcalL SOR(\omega)) ) approximates ( \rho(\mathcalL_MSOR(\omega_1,\omega_2)) ). convert msor to sor

For a system ( Ax = b ) with ( A = D - L - U ) (diagonal, strictly lower, strictly upper): So, why would one want to convert an